p^2+10p=-25

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Solution for p^2+10p=-25 equation:



p^2+10p=-25
We move all terms to the left:
p^2+10p-(-25)=0
We add all the numbers together, and all the variables
p^2+10p+25=0
a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{-10}{2}=-5$

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